I am trying to input this problem onto matlab for an assignment. It seems the e is from natural log. e^x+5 – e^1/y. Although this input is invalid in matlab. How would I go about
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=EXP () =EXP (first data from variable LnY) =EXP (2.48) =12.00 In more detail, you can see in the image below: Based on the calculations using the excel formula, the reverse
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y = log (x)/ (log (e)). But there’s a special name for a logarithmic like this. A logarithm with base e is called the “natural logarithm” and so you end up with y= ln (x). That is the inverse of e^x
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